The Equivalent of Power

A known solution for power is

P = Fv

Where F = ma, so that

P = mav

The same, using impulse p = mv, is

P = pa

Again the same, using p = [h-bar]k and ak = [alpha], the latter shown using the sum-rule

(d/dt)(dl/dt)(d[theta]/dl) = (d/dt)(d[theta]/dt), is

P = [h-bar][alpha]

Where [alpha] is the angular acceleration and is the equivalent of power.

Oegstgeest, 31 may 2012,

P.J. Brouwer

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Pieter Brouwer has written 10 post in this blog.